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# Re: Specifying the Reals in LSL?

"Stephen J. Garland" <garland> writes:
> In classical first-order logic, there is no finite axiomatization of the
>theory of the reals: it takes infinitely many axioms to express the fact that a
>field has characteristic zero, and it takes infinitely many to express the fact
>that every polynomial of odd degree has a root. However, because the
>generated-by construct in LSL is equivalent to an infinite set of formulas, it
>is possible to provide a finite axiomatization in LSL, as described above.
Thanks for all that and your answers.
I'm sorry our posts crossed, but I do think that the syntax would be
less confusing if you didn't require quantified variables to be
declared outside the scope of the equation in which they appear
in LSL.
Thanks,
Gary
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